2x-8=x^2+x

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Solution for 2x-8=x^2+x equation: 



2x-8=x^2+x

We move all terms to the left:

2x-8-(x^2+x)=0

We get rid of parentheses

-x^2+2x-x-8=0

We add all the numbers together, and all the variables

-1x^2+x-8=0

a = -1; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·(-1)·(-8)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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